3310 - n元买m鸡
时间限制 : 1 秒
内存限制 : 128 MB
<span style="font-family:黑体;font-size:12pt;">一个炊事员上街采购<span>,</span>用<span>n</span>元钱买了<span>m</span>只鸡<span>, </span>其中母鸡一只<span>15</span>元<span>,</span>公鸡一只<span>10</span>元<span>,</span>小鸡一只<span>5</span>元<span>,</span>正好把钱买完。问母鸡<span>a</span>、公鸡<span>b</span>、小鸡<span>c</span>各买多少只？ <span></span></span>
<span style="font-family:黑体;font-size:12pt;">输入<span>500 90</span></span>
<span style="font-family:黑体;font-size:12pt;">输出<span></span></span>
<span style="font-family:黑体;font-size:12pt;">mu:1<span> </span>gong:8<span> </span>xiao:81</span>
<span style="font-family:黑体;font-size:12pt;"></span><span style="font-family:黑体;font-size:12pt;"></span><span style="font-family:黑体;font-size:12pt;">mu:2<span> </span>gong:6<span> </span>xiao:82</span>
<span style="font-family:黑体;font-size:12pt;">mu:3<span> </span>gong:4 xiao:83</span>
<span style="font-family:黑体;font-size:12pt;"></span><span style="font-family:黑体;font-size:12pt;">mu:4<span> </span>gong:2<span> </span>xiao:84</span>
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C++解答
#include<iostream> using namespace std; int main(){ int x,y,z; int n,m; cin>>n>>m; for(x=0;x<=m;x++) { for(y=0;y<=m;y++) { for(z=0;z<=m;z++) { if(x+y+z==m&& 15*x+10*y+5*z==n) { if(x&&y&&z){ cout<<"mu:"<<x<<" "<<"gong:"<<y<<" "<<"xiao:"<<z<<endl; } } } } } return 0; }