3190 - 求整和

通过次数

0

提交次数

0

时间限制 : 1 秒 内存限制 : 128 MB

 

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	<span style="font-family:宋体;color:blue;font-size:20pt;">输入</span><span style="color:blue;font-size:20pt;">10</span><span style="font-family:宋体;color:blue;font-size:20pt;">个整数</span><span style="color:blue;font-size:20pt;">,</span><span style="font-family:宋体;color:blue;font-size:20pt;">求他们的和. </span>
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	<span style="color:blue;font-size:20pt;"><span></span></span><span style="font-family:宋体;color:blue;font-size:20pt;">输入</span><span style="color:blue;font-size:20pt;">10</span><span style="font-family:宋体;color:blue;font-size:20pt;">行</span><span style="color:blue;font-size:20pt;">,</span><span style="font-family:宋体;color:blue;font-size:20pt;">每行一个整数. </span>
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	<span style="font-family:宋体;color:blue;font-size:20pt;">输出一行</span><span style="color:blue;font-size:20pt;">,</span><span style="font-family:宋体;color:blue;font-size:20pt;">一个整数</span><span style="color:blue;font-size:20pt;">. </span>
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题目输入

题目输出

输入/输出样例

输入格式

10
10
10
10
10
20
20
20
20
20

输出格式

150

C语言解答

#include <stdio.h>
int a, b, i;
int main(void) {
    for (i = 1; i <= 10; i++) {
        scanf("%d", &a);
        b += a;
    }
    printf("%d\n", b);
    return 0;
}

C++解答

#include<iostream>

using namespace std;

int main()
{
	int a,b;
	b=0;
    for (int i=1;i<=10;i++)
    {
    	cin>>a;
    	b=b+a;
    }
	cout<<b<<endl;
	return 0;
}

Python解答

# coding=utf-8
t = 0
for i in range(0, 10) :
    s = int(input())
    t = t + s
print(t)