C语言解答

#include<stdio.h>
int main()
{ int i,j,n,k,s;
    k=0;j=0;s=0;
   scanf("%d",&n);
   int a[n],b[n],c[n];
   for(i=0;i<n;i++)
    scanf("%d",&a[i]);
    for(i=0;i<n;i++)
    {
        if(a[i]<=60)
        { b[k]=a[i];
            k++ ;}
        else
        {
        c[j]=a[i];
        j++;
        }
    }
    for(i=0;i<k;i++)
      {printf("%d",b[i]);
         if(i==k-1)
            break;
         else
            printf(" ");}
            printf("\n");

    for(i=0;i<j;i++)
        s=s+c[i];
    printf("%d\n",s/j);
    return 0;
}

C++解答

#include<iostream>
#include<cstdio>
#include<iostream>
#include<cmath>

using namespace std;

int main(){
    int a[105];
    int n,flag;
    while(cin>>n){
        int sum = 0,count1 = 0;
        flag = 1;
        for(int i=0;i<n;i++)
            cin>>a[i];
        for(int i=0;i<n;i++){
            if(a[i]<=60)
                if(flag){
                    flag = 0;
                    cout<<a[i];
                }
                else
                    cout<<' '<<a[i];
            else{
                sum += a[i];
                count1++;
            }
        }
        cout<<endl<<sum/count1<<endl;
    }
    return 0;
}