C语言解答

#include<stdio.h>
int sum;
int judge(int a,int b)
{
	if((a%b+a/b)/b)
	{
	sum+=(a%b+a/b)/b;
	a=a%b+a/b;
	return judge(a,b);
	}
	else
	return sum;
	
}
main()
{
	int n,m,d;
	scanf("%d",&n);
	while(n--)
	{
		sum=0;
		scanf("%d %d",&m,&d);
			sum=m+m/d;
			judge(m,d);
			printf("%d\n",sum);
	}
}

C++解答

#include <stdio.h>
int main()
{
	int n , v, k ,re , sum ,fre ,temp ,temp2;
	scanf("%d",&n);
	while(n--)
	{
		scanf("%d%d",&v,&k);
		sum = v + v / k;
		fre = v % k ;
		re = v / k ;
		temp = fre +re;
		while(temp >=k)
		{
			sum = sum + (fre + re) / k;
			temp2 = fre+re;
			temp = (fre + re) % k +(fre + re) /k;
			fre = temp2 %k;
			re = temp2 /k;
		}
		printf("%d\n",sum);
	}
}

Java解答

import java.util.Scanner;

public class Main {
	public static void main(String[] args) {
		Scanner input=new Scanner(System.in);
		int s=input.nextInt();
		int n=0,m=0;
		
		for(int i=1;i<=s;i++) {
			n=input.nextInt();
			m=input.nextInt();
			int sum=n;
			while(n/m>0) {
				sum+=n/m;
				n=n/m+n%m;
			}
			System.out.println(sum);
		}
	}
}