1945 - The Famous Clock
Mr. B, Mr. G and Mr. M are now in Warsaw, Poland, for the 2012’s ACM-ICPC World Finals Contest. They’ve decided to take a 5 hours training every day before the contest. Also, they plan to start training at 10:00 each day since the World Final Contest will do so. The scenery in Warsaw is so attractive that Mr. B would always like to take a walk outside for a while after breakfast. However, Mr. B have to go back before training starts, otherwise his teammates will be annoyed. Here is a problem: Mr. B does not have a watch. In order to know the exact time, he has bought a new watch in Warsaw, but all the numbers on that watch are represented in Roman Numerals. Mr. B cannot understand such kind of numbers. Can you translate for him?
题目输入
Each test case contains a single line indicating a Roman Numerals that to be translated. All the numbers can be found on clocks. That is, each number in the input represents an integer between 1 and 12. Roman Numerals are expressed by strings consisting of uppercase ‘I’, ‘V’ and ‘X’. See the sample input for further information.
题目输出
For each test case, display a single line containing a decimal number corresponding to the given Roman Numerals.
输入/输出样例
输入格式
I II III IV V VI VII VIII IX X XI XII
输出格式
Case 1: 1 Case 2: 2 Case 3: 3 Case 4: 4 Case 5: 5 Case 6: 6 Case 7: 7 Case 8: 8 Case 9: 9 Case 10: 10 Case 11: 11 Case 12: 12
C语言解答
#include<stdio.h> #include<string.h> int main() { char a[10],i=0; while(~scanf("%s",a)) { i++; if(!strcmp(a,"I")) printf("Case %d: 1\n",i); else if(!strcmp(a,"II")) printf("Case %d: 2\n",i); else if(!strcmp(a,"III")) printf("Case %d: 3\n",i); else if(!strcmp(a,"IV")) printf("Case %d: 4\n",i); else if(!strcmp(a,"V")) printf("Case %d: 5\n",i); else if(!strcmp(a,"VI")) printf("Case %d: 6\n",i); else if(!strcmp(a,"VII")) printf("Case %d: 7\n",i); else if(!strcmp(a,"VIII")) printf("Case %d: 8\n",i); else if(!strcmp(a,"IX")) printf("Case %d: 9\n",i); else if(!strcmp(a,"X")) printf("Case %d: 10\n",i); else if(!strcmp(a,"XI")) printf("Case %d: 11\n",i); else if(!strcmp(a,"XII")) printf("Case %d: 12\n",i); } return 0; }
C++解答
#include<iostream> #include<stdio.h> #include<string> using namespace std; int main() { int n=0,k; string a; while(cin>>a) { printf("Case %d: ",++n); if(a=="I")cout<<1<<endl; else if(a=="II")cout<<2<<endl; else if(a=="III")cout<<3<<endl; else if(a=="IV")cout<<4<<endl; else if(a=="V")cout<<5<<endl; else if(a=="VI")cout<<6<<endl; else if(a=="VII")cout<<7<<endl; else if(a=="VIII")cout<<8<<endl; else if(a=="IX")cout<<9<<endl; else if(a=="X")cout<<10<<endl; else if(a=="XI")cout<<11<<endl; else cout<<12<<endl; } return 0; }