1638 - Primary Arithmetic
时间限制 : 1 秒
内存限制 : 32 MB
Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the "carry" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.
题目输入
Each line of input contains two unsigned integers less than 10 digits. The last line of input contains 0 0.
题目输出
For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.
输入/输出样例
输入格式
555 445 4325 5996 8 1 0 0
输出格式
1 carry operation. 3 carry operations. NO carry operation.
C语言解答
#include <stdio.h> #include <stdlib.h> #include <string.h> int main() { unsigned int a; unsigned int b; while(scanf("%d%d",&a,&b) != EOF){ if(a==0 && b==0)break; char temp2[20], temp1[20]; sprintf(temp1,"%d",a); sprintf(temp2,"%d",b); int ans = 0; for(int i = strlen(temp1),j = strlen(temp2);i >= 0&&j >= 0; i--, j--){ if(temp1[i]-'0' + temp2[j]-'0' >= 10)ans++; } if(ans==1) printf("%d carry operation.\n",ans); if(ans>1) printf("%d carry operations.\n",ans); if(ans==0) printf("NO carry operation.\n"); } return 0; }
C++解答
#include "stdio.h" int main() { int a,b,c; while(1) { int x = 0; scanf("%d%d",&a,&b); if(a == 0 && b == 0) break; while(a>0 && b>0) { if(a%10 + b%10 >= 10) x++;//只是按位相加，1+999只有1个进位！！--不考虑进位带来新的进位。 a /= 10; b /= 10; } if(x == 0) printf("NO carry operation.\n"); else if(x == 1) printf("1 carry operation.\n"); else printf("%d carry operations.\n",x); } return 0; }