C语言解答

#include<stdio.h>
#include<string.h>

int t[4000];

int chang(int a[4000],int b)
{
    int c=0;
    while(b!=0)
    {
        if(a[0]!=1)
        {
            if(a[b-1]%2==1)
                t[c]=1;
            else
                t[c]=0;
            for(int i=0; i<b; i++)
            {
                if(a[i]%2==1)
                {
                    a[i+1]+=10;
                }
                a[i]=a[i]/2;
            }
            c++;
        }
        else
        {
            if(a[b-1]%2==1)
                t[c]=1;
            else
                t[c]=0;
            a[1]+=10;
            for(int i=1; i<b; i++)
            {
                if(a[i]%2==1)
                {
                    a[i+1]+=10;
                }
                a[i-1]=a[i]/2;
            }
            a[b-1]=0;
            b=b-1;
            c++;
        }
    }
    return c;

}

int main()
{
    char a[4000];
    int b[4000],c,d,e[4000];
    memset(t,0,sizeof(t));
    memset(a,0,sizeof(a));
    memset(b,0,sizeof(b));
    memset(e,0,sizeof(e));
    while(scanf("%s",a)!=EOF)
    {
        c=strlen(a);
        if(a[1]=='\0'&&a[0]=='0')
        {
       A1 : printf("0\n");
            continue;
        }

        for(int i=0; i<c; i++)
        {
            b[i]=a[i]-48;
        }
         while(b[0]==0)
        {
            for(int i=0;i<c;i++)
            {
                b[i]=b[i+1];
            }
            c--;
            if (c==0)
            goto A1;
        }

        d = chang(b,c);
        for(int i=0; i<d; i++)
        {
            e[i]=t[d-i-1];
        }

        for(int i=0; i<d; i++)
        {
            printf("%d",e[i]);
        }
        printf("\n");
        memset(t,0,sizeof(t));
        memset(a,0,sizeof(a));
        memset(b,0,sizeof(b));
        memset(e,0,sizeof(e));
    }
    return 0;
}

C++解答

#include<stdio.h>
#include<string.h>

char result[1000];

void base_convert(char num[],int s,int e)
{
	int i,flag,k,j,a[1000],b[1000];
	for(i=0;i<strlen(num);i++)
		a[i]=num[i]-48;
	k=0;
	while(1)
	{
		for(i=0;i<strlen(num);i++)
		{
			if(a[i]!=0&&i<strlen(num)-1)
			{
				a[i+1]+=(a[i]%e)*s;
				a[i]/=e;
			}
			if(i==strlen(num)-1)
			{
				b[k++]=a[i]%e;
				a[i]/=e;
			}
		}
		flag=0;
		for(i=0;i<strlen(num);i++)
			if(a[i]!=0)
				flag=1;
		if(!flag)
			break;
	}
	for(j=0,i=k-1;i>=0;i--)
		result[j++]=b[i]+48;
	result[j]='\0';
}

int main()
{
	char n[31];
	while(scanf("%s",n)!=EOF)
	{
		base_convert(n,10,2);
		puts(result);
	}
	return 0;
}

Java解答

import java.math.BigInteger;
import java.util.Scanner;
public class Main{
	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		while(cin.hasNext()){
			System.out.println(new BigInteger(cin.next()).toString(2));
		}
	}
}

Python解答

# coding=utf-8
import sys

for line in sys.stdin.readlines():
    print(bin(int(line)).replace('0b',''))