C语言解答

int main(int argc, char* argv[])
{ 
	double m,n,sum,i;
	while(~scanf("%lf%lf",&m,&n))
	{
		sum=m;
	  for(i=0;i<n;i++)
	  {   
		  sum+=m;
		  m*=1.0/2;
	  }
	  sum-=2*m;
	 printf("%.2lf %.2lf\n",m,sum);
	}
	return 0;
}

C++解答

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
	double n,sum;
	int m;
	cin>>n>>m;
	sum=-n;
	for (int i=1; i<=m; i++)
	{
		sum+=2*n;
		n/=2;
	}
	printf("%.2lf %.2lf\n",n,sum);
	return 0;
}