3325 - 例题5-1-2 连续自然数求和

无

5050

Solution C

#include<stdio.h>
int main()
{
	int sum=1,i=2;
	do
	{
		sum += i;
		i++;
	}
	while(i<=100);
	printf("%d\n",sum);
	getchar();
	return 0;
}

Solution C++

#include <cstdio>
int main (void){
	int n=1,sum=0;
	do{
		sum=sum+n;
		n++;
	}while(n<=100);
	printf("%d\n",sum);
	return 0;
}