2603 - 判断升序
实现public static boolean isSorted(int[] table)
判断整数数组元素是否已经按升序排序。
题目输入
一列数,需要判断的数组元素。
题目输出
如果已经排序输出YES
如果没有排序输出NO
输入/输出样例
题目输入
1 2 3 4 5 6
题目输出
YES
提示
import java.util.*;
public class Main{
public static void main(String args[]){
Scanner cin = new Scanner(System.in);
int a, b;
b=-1;
while (cin.hasNext()){a = cin.nextInt();
if(??????????){
????????;
????????????????????;
}
????????????;}
if(!cin.hasNext())
????????????????????????}
}
C语言解答
#include<stdio.h> void main() { int a,b,t; scanf("%d",&b); while(scanf("%d",&a)!=EOF) { if(a<b) { printf("NO"); goto L; } else { t=a;a=b;b=t; } } printf("YES"); L: ; }
C++解答
#include <stdio.h> #define maxSize 1000 bool isSorted(int *arr, int n) { int i, j; for (i = 0; i < n; ++i) { for (j = i+1; j < n; ++j) { if (*(arr+i) > *(arr+j)) { return false; } } } return true; } int main() { int num, count = 0; int arr[maxSize]; while (scanf("%d", &num) != EOF) { arr[count++] = num; } bool flag = isSorted(arr, count); if (flag) { printf("YES\n"); } else { printf("NO\n"); } return 0; }
提示
import java.util.*;
public class Main{
public static void main(String args[]){
Scanner cin = new Scanner(System.in);
int a, b;
b=-1;
while (cin.hasNext()){
a = cin.nextInt();
if(??????????){
????????;
????????????????????;
}
????????????;
}
if(!cin.hasNext())
????????????????????????
}
}