2494 - 英文数字
在这个问题中，你将会给出一个或多个用英文表示的数。你的任务就是把这些英文标识的数翻译为阿拉伯数字。
给定数字的范围从-999，999，999到999，999，999.以下一些详细的英文单词表，你的程序将会使用到：
negative,zero,one,two,three,four,five,six,seven,eight,nine,ten,eleven,twelve,thirteen,fourteen,fifteen,
sixteen,seventeen,eighteen,nineteen,twenty,thirty,forty,sixty,seventy,eighty,ninety,hundred,thousand,million.
Input
输入注意事项：
1、负数将会被描述为negative。
2、当“thousand”可以使用时，“hundred”不能用。例如：1500会被描述为“one thousand five hundred”而不是"fifteen hundred"
结尾以空行结束
Output
每个结果占一行
Examples
Input
six negative seven hundred twenty nine one million one hundred one eight hundred fourteen thousand twenty two
Output
6 -729 1000101 814022
Solution C
#include<stdio.h> #include<string.h> int main() { char s[10],ch; int sum=0,ans=0; while(scanf("%s",s)!=EOF) { if(!strcmp(s,"negative")) printf("-"); else if(!strcmp(s,"zero")) sum+=0; else if(!strcmp(s,"one")) sum+=1; else if(!strcmp(s,"two")) sum+=2; else if(!strcmp(s,"three")) sum+=3; else if(!strcmp(s,"four")) sum+=4; else if(!strcmp(s,"five")) sum+=5; else if(!strcmp(s,"six")) sum+=6; else if(!strcmp(s,"seven")) sum+=7; else if(!strcmp(s,"eight")) sum+=8; else if(!strcmp(s,"nine")) sum+=9; else if(!strcmp(s,"ten")) sum+=10; else if(!strcmp(s,"eleven")) sum+=11; else if(!strcmp(s,"twelve")) sum+=12; else if(!strcmp(s,"thirteen")) sum+=13; else if(!strcmp(s,"fourteen")) sum+=14; else if(!strcmp(s,"fifteen")) sum+=15; else if(!strcmp(s,"sixteen")) sum+=16; else if(!strcmp(s,"seventeen"))sum+=17; else if(!strcmp(s,"eighteen")) sum+=18; else if(!strcmp(s,"nineteen")) sum+=19; else if(!strcmp(s,"twenty")) sum+=20; else if(!strcmp(s,"thirty")) sum+=30; else if(!strcmp(s,"forty")) sum+=40; else if(!strcmp(s,"fifty")) sum+=50; else if(!strcmp(s,"sixty")) sum+=60; else if(!strcmp(s,"seventy")) sum+=70; else if(!strcmp(s,"eighty")) sum+=80; else if(!strcmp(s,"ninety")) sum+=90; else if(!strcmp(s,"hundred")) sum*=100; else if(!strcmp(s,"thousand")) { ans+=sum*1000; sum=0; } else if(!strcmp(s,"million")) { ans+=sum*1000000; sum=0; } ch=getchar(); if(ch=='\n') { printf("%d\n",ans+sum); sum=0; ans=0; } } return 0; }
Solution C++
#include<iostream> #include<cstdio> #include<cstring> #define maxn 100 char s[maxn]; int sum=0,ans=0; int main() { while(scanf("%s",s)!=EOF) { if(!strcmp(s,"negative"))printf("-"); else if(!strcmp(s,"zero"))sum+=0; else if(!strcmp(s,"one"))sum+=1; else if(!strcmp(s,"two"))sum+=2; else if(!strcmp(s,"three"))sum+=3; else if(!strcmp(s,"four"))sum+=4; else if(!strcmp(s,"five"))sum+=5; else if(!strcmp(s,"six"))sum+=6; else if(!strcmp(s,"seven"))sum+=7; else if(!strcmp(s,"eight"))sum+=8; else if(!strcmp(s,"nine"))sum+=9; else if(!strcmp(s,"ten"))sum+=10; else if(!strcmp(s,"eleven"))sum+=11; else if(!strcmp(s,"twelve"))sum+=12; else if(!strcmp(s,"thirteen"))sum+=13; else if(!strcmp(s,"fourteen"))sum+=14; else if(!strcmp(s,"fifteen"))sum+=15; else if(!strcmp(s,"sixteen"))sum+=16; else if(!strcmp(s,"seventeen"))sum+=17; else if(!strcmp(s,"eighteen"))sum+=18; else if(!strcmp(s,"nineteen"))sum+=19; else if(!strcmp(s,"twenty"))sum+=20; else if(!strcmp(s,"thirty"))sum+=30; else if(!strcmp(s,"forty"))sum+=40; else if(!strcmp(s,"fifty"))sum+=50; else if(!strcmp(s,"sixty"))sum+=60; else if(!strcmp(s,"seventy"))sum+=70; else if(!strcmp(s,"eighty"))sum+=80; else if(!strcmp(s,"ninety"))sum+=90; else if(!strcmp(s,"hundred")) { sum*=100; } else if(!strcmp(s,"thousand")) { ans+=sum*1000; sum=0; } else if(!strcmp(s,"million")) { ans+=sum*1000000; sum=0; } char ch=getchar(); if(ch=='\n') { printf("%d\n",ans+sum); sum=0; ans=0; } } return 0; }