2171 - 打印星形三角(II)

5

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Solution C

#include<stdio.h>
int main(){
int N,i,sum=0,j=1;
int flag=0;
scanf("%d",&N);
for(i=1;i<=N;i++){
    sum=sum+i;
    for(j=j;j<=sum;j++){
        if(flag) printf(" ");
        printf("%d",j);
        flag=1;
    }
if((j==sum)&&(i==N)) break;
else{
    printf("\n");
    flag=0;}
}

return 0;
}

Solution C++

#include <iostream>
#include <iomanip>
using namespace std;


int main()
{
    int count  = 1;
    int n;
    while (cin>>n)
    {       
        for (int i = 1; i<=n; i++)
        {
            for (int j = 1; j<=i; j++)
            {
                cout<<count++;
                if (j < i)
                    cout<< " ";
                 
            }
            cout<<endl;
        }
    }

    return 0;
}