2087 - 计算偶数和

10
1 2 3 4 5 6 7 8 9 10

30

Solution C

#include <stdio.h>
int main(int argc, char *argv[])
{
	int n,num,sum=0;
	scanf("%d",&n);
	for(;n>0;n--)
	{
		scanf("%d",&num);
		if(num%2==0)
		sum+=num;
	}
	printf("%d",sum);
	return 0;
}

Solution C++

#include<iostream>
using namespace std;
int main()
{
	int n,x,ans=0;
	cin>>n;
	for (int i=1; i<=n; i++)
	{
		cin>>x;
		if (x%2==0) ans+=x;
	}
	cout<<ans<<endl;
	return 0;
}