1293 - 2010年上半年浙江省高等学校计算机等级考试-编程题1

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数组a中所有奇数之和2500

Solution C

#include <stdio.h>

int main(int argc, char const *argv[])
{
	int a[100];
	int sum = 0;
	for (int i = 0; i < 100; ++i)
	{
		scanf("%d",&a[i]);
		if (a[i] % 2 != 0 )
			sum += a[i];
	}

	printf("数组a中所有奇数之和%d\n",sum);

	return 0;
}

Solution C++

#include<iostream>
using namespace std;
#define N 100

int main() {
	int a[N];                                 //array
	int sum = 0;
	for(int i=0; i<N; ++i){
		cin >> a[i];
	}
	for(int i=0; i<N; ++i){
		if(a[i] %2 != 0){
			sum += a[i];
		}
	}
	cout << "数组a中所有奇数之和" << sum << endl;
	return 0;
}